9x^2-120x+400=0

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Solution for 9x^2-120x+400=0 equation: 



9x^2-120x+400=0

a = 9; b = -120; c = +400;
Δ = b2-4ac
Δ = -1202-4·9·400
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{120}{18}=6+2/3$

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